Optimal. Leaf size=89 \[ \frac {\tanh ^{-1}\left (\frac {\sqrt {a+b \sec ^2(e+f x)}}{\sqrt {a}}\right )}{a^{5/2} f}-\frac {1}{a^2 f \sqrt {a+b \sec ^2(e+f x)}}-\frac {a+b}{3 a b f \left (a+b \sec ^2(e+f x)\right )^{3/2}} \]
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Rubi [A] time = 0.13, antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {4139, 446, 78, 51, 63, 208} \[ -\frac {1}{a^2 f \sqrt {a+b \sec ^2(e+f x)}}+\frac {\tanh ^{-1}\left (\frac {\sqrt {a+b \sec ^2(e+f x)}}{\sqrt {a}}\right )}{a^{5/2} f}-\frac {a+b}{3 a b f \left (a+b \sec ^2(e+f x)\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 51
Rule 63
Rule 78
Rule 208
Rule 446
Rule 4139
Rubi steps
\begin {align*} \int \frac {\tan ^3(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {-1+x^2}{x \left (a+b x^2\right )^{5/2}} \, dx,x,\sec (e+f x)\right )}{f}\\ &=\frac {\operatorname {Subst}\left (\int \frac {-1+x}{x (a+b x)^{5/2}} \, dx,x,\sec ^2(e+f x)\right )}{2 f}\\ &=-\frac {a+b}{3 a b f \left (a+b \sec ^2(e+f x)\right )^{3/2}}-\frac {\operatorname {Subst}\left (\int \frac {1}{x (a+b x)^{3/2}} \, dx,x,\sec ^2(e+f x)\right )}{2 a f}\\ &=-\frac {a+b}{3 a b f \left (a+b \sec ^2(e+f x)\right )^{3/2}}-\frac {1}{a^2 f \sqrt {a+b \sec ^2(e+f x)}}-\frac {\operatorname {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,\sec ^2(e+f x)\right )}{2 a^2 f}\\ &=-\frac {a+b}{3 a b f \left (a+b \sec ^2(e+f x)\right )^{3/2}}-\frac {1}{a^2 f \sqrt {a+b \sec ^2(e+f x)}}-\frac {\operatorname {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \sec ^2(e+f x)}\right )}{a^2 b f}\\ &=\frac {\tanh ^{-1}\left (\frac {\sqrt {a+b \sec ^2(e+f x)}}{\sqrt {a}}\right )}{a^{5/2} f}-\frac {a+b}{3 a b f \left (a+b \sec ^2(e+f x)\right )^{3/2}}-\frac {1}{a^2 f \sqrt {a+b \sec ^2(e+f x)}}\\ \end {align*}
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Mathematica [C] time = 10.17, size = 613, normalized size = 6.89 \[ -\frac {e^{i (e+f x)} \sec ^5(e+f x) \sqrt {4 b+a e^{-2 i (e+f x)} \left (1+e^{2 i (e+f x)}\right )^2} \left (\frac {-12 \log \left (\sqrt {a} \sqrt {a \left (1+e^{2 i (e+f x)}\right )^2+4 b e^{2 i (e+f x)}}+a e^{2 i (e+f x)}+a+2 b\right )-12 \log \left (\sqrt {a} \sqrt {a \left (1+e^{2 i (e+f x)}\right )^2+4 b e^{2 i (e+f x)}}+a e^{2 i (e+f x)}+a+2 b e^{2 i (e+f x)}\right )+24 i f x}{\sqrt {a \left (1+e^{2 i (e+f x)}\right )^2+4 b e^{2 i (e+f x)}}}-\frac {\sqrt {a} \left (1+e^{2 i (e+f x)}\right ) \left (a^3 \left (1+e^{2 i (e+f x)}\right )^2-6 a^2 b \left (e^{2 i (e+f x)}+e^{4 i (e+f x)}+1\right )-32 a b^2 \left (1+e^{2 i (e+f x)}\right )^2-96 b^3 e^{2 i (e+f x)}\right )}{b^2 \left (a \left (1+e^{2 i (e+f x)}\right )^2+4 b e^{2 i (e+f x)}\right )^2}\right ) (a \cos (2 e+2 f x)+a+2 b)^{5/2}}{96 \sqrt {2} a^{5/2} f \left (a+b \sec ^2(e+f x)\right )^{5/2}}-\frac {\sec ^4(e+f x) (a \cos (2 (e+f x))+a+3 b) (a \cos (2 e+2 f x)+a+2 b)^{5/2}}{48 b^2 f (a \cos (2 (e+f x))+a+2 b)^{3/2} \left (a+b \sec ^2(e+f x)\right )^{5/2}}+\frac {\sec ^4(e+f x) ((a-2 b) \cos (2 (e+f x))+a+b) (a \cos (2 e+2 f x)+a+2 b)^{5/2}}{96 b^2 f (a \cos (2 (e+f x))+a+2 b)^{3/2} \left (a+b \sec ^2(e+f x)\right )^{5/2}} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.50, size = 522, normalized size = 5.87 \[ \left [\frac {3 \, {\left (a^{2} b \cos \left (f x + e\right )^{4} + 2 \, a b^{2} \cos \left (f x + e\right )^{2} + b^{3}\right )} \sqrt {a} \log \left (128 \, a^{4} \cos \left (f x + e\right )^{8} + 256 \, a^{3} b \cos \left (f x + e\right )^{6} + 160 \, a^{2} b^{2} \cos \left (f x + e\right )^{4} + 32 \, a b^{3} \cos \left (f x + e\right )^{2} + b^{4} + 8 \, {\left (16 \, a^{3} \cos \left (f x + e\right )^{8} + 24 \, a^{2} b \cos \left (f x + e\right )^{6} + 10 \, a b^{2} \cos \left (f x + e\right )^{4} + b^{3} \cos \left (f x + e\right )^{2}\right )} \sqrt {a} \sqrt {\frac {a \cos \left (f x + e\right )^{2} + b}{\cos \left (f x + e\right )^{2}}}\right ) - 8 \, {\left (3 \, a b^{2} \cos \left (f x + e\right )^{2} + {\left (a^{3} + 4 \, a^{2} b\right )} \cos \left (f x + e\right )^{4}\right )} \sqrt {\frac {a \cos \left (f x + e\right )^{2} + b}{\cos \left (f x + e\right )^{2}}}}{24 \, {\left (a^{5} b f \cos \left (f x + e\right )^{4} + 2 \, a^{4} b^{2} f \cos \left (f x + e\right )^{2} + a^{3} b^{3} f\right )}}, -\frac {3 \, {\left (a^{2} b \cos \left (f x + e\right )^{4} + 2 \, a b^{2} \cos \left (f x + e\right )^{2} + b^{3}\right )} \sqrt {-a} \arctan \left (\frac {{\left (8 \, a^{2} \cos \left (f x + e\right )^{4} + 8 \, a b \cos \left (f x + e\right )^{2} + b^{2}\right )} \sqrt {-a} \sqrt {\frac {a \cos \left (f x + e\right )^{2} + b}{\cos \left (f x + e\right )^{2}}}}{4 \, {\left (2 \, a^{3} \cos \left (f x + e\right )^{4} + 3 \, a^{2} b \cos \left (f x + e\right )^{2} + a b^{2}\right )}}\right ) + 4 \, {\left (3 \, a b^{2} \cos \left (f x + e\right )^{2} + {\left (a^{3} + 4 \, a^{2} b\right )} \cos \left (f x + e\right )^{4}\right )} \sqrt {\frac {a \cos \left (f x + e\right )^{2} + b}{\cos \left (f x + e\right )^{2}}}}{12 \, {\left (a^{5} b f \cos \left (f x + e\right )^{4} + 2 \, a^{4} b^{2} f \cos \left (f x + e\right )^{2} + a^{3} b^{3} f\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: NotImplementedError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 3.20, size = 10839, normalized size = 121.79 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {tan}\left (e+f\,x\right )}^3}{{\left (a+\frac {b}{{\cos \left (e+f\,x\right )}^2}\right )}^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\tan ^{3}{\left (e + f x \right )}}{\left (a + b \sec ^{2}{\left (e + f x \right )}\right )^{\frac {5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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